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문의드립니다^^

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원칙지킴이
2016-09-22 13:43:00
130
글번호 102114
답변완료
1.주기준 input : Per1(23.6),Per2(38.2),Per3(50.0),Per4(61.8),Per5(76.4); var : HH(0),LL(0); if index == 0 or DayOfWeek(date) < dayofweek(date[1]) then{ HH = H; LL = L; } if H > HH Then HH = H; if L < LL Then LL = L; var1 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per1/100)); var2 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per2/100)); var3 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per3/100)); var4 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per4/100)); var5 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per5/100)); plot1(var1,"23.6"); plot2(var2,"38.2"); plot3(var3,"50.0"); plot4(var4,"61.8"); plot5(var5,"76.4"); 2 일기준이면 아래식입니다. input : Per1(23.6),Per2(38.2),Per3(50.0),Per4(61.8),Per5(76.4); var : HH(0),LL(0); if index == 0 or date != date[1] then{ HH = H; LL = L; } if H > HH Then HH = H; if L < LL Then LL = L; var1 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per1/100)); var2 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per2/100)); var3 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per3/100)); var4 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per4/100)); var5 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per5/100)); plot1(var1,"23.6"); plot2(var2,"38.2"); plot3(var3,"50.0"); plot4(var4,"61.8"); plot5(var5,"76.4"); 위 둘 식 각각에 해당주 와 해당일 각각 최고점과 최저점을 일직선으로 &#51067;는 고저라인을 넣고 싶습니다. 그래서 로그변환 피보나치 수열과 함께 총 7개의 라인이 나올 수 있으면 좋겠습니다. 겹치지 않구요. 매번 감사드립니다.
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예스스탁 예스스탁 답변

2016-09-22 15:46:54

안녕하세요 예스스탁입니다. 1. input : Per1(23.6),Per2(38.2),Per3(50.0),Per4(61.8),Per5(76.4); var : HH(0),LL(0); if index == 0 or DayOfWeek(date) < dayofweek(date[1]) then{ HH = H; LL = L; } if H > HH Then HH = H; if L < LL Then LL = L; var1 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(0)); var2 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per1/100)); var3 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per2/100)); var4 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per3/100)); var5 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per4/100)); var6 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per5/100)); var7 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(100/100)); plot1(var1,"최고"); plot2(var2,"23.6"); plot3(var3,"38.2"); plot4(var4,"50.0"); plot5(var5,"61.8"); plot6(var6,"76.4"); plot7(var7,"최저"); 2 input : Per1(23.6),Per2(38.2),Per3(50.0),Per4(61.8),Per5(76.4); var : HH(0),LL(0); if index == 0 or date != date[1] then{ HH = H; LL = L; } if H > HH Then HH = H; if L < LL Then LL = L; var1 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(0)); var2 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per1/100)); var3 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per2/100)); var4 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per3/100)); var5 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per4/100)); var6 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per5/100)); var7 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(100/100)); plot1(var1,"최고"); plot2(var2,"23.6"); plot3(var3,"38.2"); plot4(var4,"50.0"); plot5(var5,"61.8"); plot6(var6,"76.4"); plot7(var7,"최저"); 즐거운 하루되세요 > 원칙지킴이 님이 쓴 글입니다. > 제목 : 문의드립니다^^ > 1.주기준 input : Per1(23.6),Per2(38.2),Per3(50.0),Per4(61.8),Per5(76.4); var : HH(0),LL(0); if index == 0 or DayOfWeek(date) < dayofweek(date[1]) then{ HH = H; LL = L; } if H > HH Then HH = H; if L < LL Then LL = L; var1 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per1/100)); var2 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per2/100)); var3 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per3/100)); var4 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per4/100)); var5 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per5/100)); plot1(var1,"23.6"); plot2(var2,"38.2"); plot3(var3,"50.0"); plot4(var4,"61.8"); plot5(var5,"76.4"); 2 일기준이면 아래식입니다. input : Per1(23.6),Per2(38.2),Per3(50.0),Per4(61.8),Per5(76.4); var : HH(0),LL(0); if index == 0 or date != date[1] then{ HH = H; LL = L; } if H > HH Then HH = H; if L < LL Then LL = L; var1 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per1/100)); var2 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per2/100)); var3 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per3/100)); var4 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per4/100)); var5 = 10^(LOG10(HH)-(LOG10(HH)-LOG10(LL))*(Per5/100)); plot1(var1,"23.6"); plot2(var2,"38.2"); plot3(var3,"50.0"); plot4(var4,"61.8"); plot5(var5,"76.4"); 위 둘 식 각각에 해당주 와 해당일 각각 최고점과 최저점을 일직선으로 &#51067;는 고저라인을 넣고 싶습니다. 그래서 로그변환 피보나치 수열과 함께 총 7개의 라인이 나올 수 있으면 좋겠습니다. 겹치지 않구요. 매번 감사드립니다.
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